Integrand size = 23, antiderivative size = 161 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^5} \, dx=-\frac {b c d^2}{12 x^3}-\frac {i b c^2 d^2}{3 x^2}+\frac {3 b c^3 d^2}{4 x}-\frac {d^2 (a+b \arctan (c x))}{4 x^4}-\frac {2 i c d^2 (a+b \arctan (c x))}{3 x^3}+\frac {c^2 d^2 (a+b \arctan (c x))}{2 x^2}-\frac {2}{3} i b c^4 d^2 \log (x)-\frac {1}{24} i b c^4 d^2 \log (i-c x)+\frac {17}{24} i b c^4 d^2 \log (i+c x) \]
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Time = 0.11 (sec) , antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {45, 4992, 12, 1816} \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^5} \, dx=\frac {c^2 d^2 (a+b \arctan (c x))}{2 x^2}-\frac {d^2 (a+b \arctan (c x))}{4 x^4}-\frac {2 i c d^2 (a+b \arctan (c x))}{3 x^3}-\frac {2}{3} i b c^4 d^2 \log (x)-\frac {1}{24} i b c^4 d^2 \log (-c x+i)+\frac {17}{24} i b c^4 d^2 \log (c x+i)+\frac {3 b c^3 d^2}{4 x}-\frac {i b c^2 d^2}{3 x^2}-\frac {b c d^2}{12 x^3} \]
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Rule 12
Rule 45
Rule 1816
Rule 4992
Rubi steps \begin{align*} \text {integral}& = -\frac {d^2 (a+b \arctan (c x))}{4 x^4}-\frac {2 i c d^2 (a+b \arctan (c x))}{3 x^3}+\frac {c^2 d^2 (a+b \arctan (c x))}{2 x^2}-(b c) \int \frac {d^2 \left (-3-8 i c x+6 c^2 x^2\right )}{12 x^4 \left (1+c^2 x^2\right )} \, dx \\ & = -\frac {d^2 (a+b \arctan (c x))}{4 x^4}-\frac {2 i c d^2 (a+b \arctan (c x))}{3 x^3}+\frac {c^2 d^2 (a+b \arctan (c x))}{2 x^2}-\frac {1}{12} \left (b c d^2\right ) \int \frac {-3-8 i c x+6 c^2 x^2}{x^4 \left (1+c^2 x^2\right )} \, dx \\ & = -\frac {d^2 (a+b \arctan (c x))}{4 x^4}-\frac {2 i c d^2 (a+b \arctan (c x))}{3 x^3}+\frac {c^2 d^2 (a+b \arctan (c x))}{2 x^2}-\frac {1}{12} \left (b c d^2\right ) \int \left (-\frac {3}{x^4}-\frac {8 i c}{x^3}+\frac {9 c^2}{x^2}+\frac {8 i c^3}{x}+\frac {i c^4}{2 (-i+c x)}-\frac {17 i c^4}{2 (i+c x)}\right ) \, dx \\ & = -\frac {b c d^2}{12 x^3}-\frac {i b c^2 d^2}{3 x^2}+\frac {3 b c^3 d^2}{4 x}-\frac {d^2 (a+b \arctan (c x))}{4 x^4}-\frac {2 i c d^2 (a+b \arctan (c x))}{3 x^3}+\frac {c^2 d^2 (a+b \arctan (c x))}{2 x^2}-\frac {2}{3} i b c^4 d^2 \log (x)-\frac {1}{24} i b c^4 d^2 \log (i-c x)+\frac {17}{24} i b c^4 d^2 \log (i+c x) \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.06 (sec) , antiderivative size = 152, normalized size of antiderivative = 0.94 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^5} \, dx=\frac {d^2 \left (-3 a-8 i a c x+6 a c^2 x^2-4 i b c^2 x^2-3 b \arctan (c x)-8 i b c x \arctan (c x)+6 b c^2 x^2 \arctan (c x)-b c x \operatorname {Hypergeometric2F1}\left (-\frac {3}{2},1,-\frac {1}{2},-c^2 x^2\right )+6 b c^3 x^3 \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1,\frac {1}{2},-c^2 x^2\right )-8 i b c^4 x^4 \log (x)+4 i b c^4 x^4 \log \left (1+c^2 x^2\right )\right )}{12 x^4} \]
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Time = 1.35 (sec) , antiderivative size = 125, normalized size of antiderivative = 0.78
method | result | size |
parts | \(a \,d^{2} \left (\frac {c^{2}}{2 x^{2}}-\frac {1}{4 x^{4}}-\frac {2 i c}{3 x^{3}}\right )+b \,d^{2} c^{4} \left (-\frac {\arctan \left (c x \right )}{4 c^{4} x^{4}}-\frac {2 i \arctan \left (c x \right )}{3 c^{3} x^{3}}+\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i}{3 c^{2} x^{2}}-\frac {2 i \ln \left (c x \right )}{3}-\frac {1}{12 c^{3} x^{3}}+\frac {3}{4 c x}+\frac {i \ln \left (c^{2} x^{2}+1\right )}{3}+\frac {3 \arctan \left (c x \right )}{4}\right )\) | \(125\) |
derivativedivides | \(c^{4} \left (a \,d^{2} \left (-\frac {1}{4 c^{4} x^{4}}-\frac {2 i}{3 c^{3} x^{3}}+\frac {1}{2 c^{2} x^{2}}\right )+b \,d^{2} \left (-\frac {\arctan \left (c x \right )}{4 c^{4} x^{4}}-\frac {2 i \arctan \left (c x \right )}{3 c^{3} x^{3}}+\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i}{3 c^{2} x^{2}}-\frac {2 i \ln \left (c x \right )}{3}-\frac {1}{12 c^{3} x^{3}}+\frac {3}{4 c x}+\frac {i \ln \left (c^{2} x^{2}+1\right )}{3}+\frac {3 \arctan \left (c x \right )}{4}\right )\right )\) | \(131\) |
default | \(c^{4} \left (a \,d^{2} \left (-\frac {1}{4 c^{4} x^{4}}-\frac {2 i}{3 c^{3} x^{3}}+\frac {1}{2 c^{2} x^{2}}\right )+b \,d^{2} \left (-\frac {\arctan \left (c x \right )}{4 c^{4} x^{4}}-\frac {2 i \arctan \left (c x \right )}{3 c^{3} x^{3}}+\frac {\arctan \left (c x \right )}{2 c^{2} x^{2}}-\frac {i}{3 c^{2} x^{2}}-\frac {2 i \ln \left (c x \right )}{3}-\frac {1}{12 c^{3} x^{3}}+\frac {3}{4 c x}+\frac {i \ln \left (c^{2} x^{2}+1\right )}{3}+\frac {3 \arctan \left (c x \right )}{4}\right )\right )\) | \(131\) |
risch | \(-\frac {i b \,d^{2} \left (6 c^{2} x^{2}-8 i c x -3\right ) \ln \left (i c x +1\right )}{24 x^{4}}+\frac {i d^{2} \left (17 b \,c^{4} \ln \left (-99 c x -99 i\right ) x^{4}-b \,c^{4} \ln \left (45 c x -45 i\right ) x^{4}-16 b \,c^{4} \ln \left (-165 c x \right ) x^{4}+6 x^{2} b \ln \left (-i c x +1\right ) c^{2}-18 i b \,c^{3} x^{3}-8 b \,c^{2} x^{2}-12 i a \,c^{2} x^{2}-16 c x a -8 i b c x \ln \left (-i c x +1\right )-3 b \ln \left (-i c x +1\right )+2 i b c x +6 i a \right )}{24 x^{4}}\) | \(179\) |
parallelrisch | \(\frac {4 i c^{4} b \,d^{2} \ln \left (c^{2} x^{2}+1\right ) x^{4}-8 i c^{4} b \,d^{2} \ln \left (x \right ) x^{4}+4 i x^{4} b \,c^{4} d^{2}+9 x^{4} \arctan \left (c x \right ) b \,c^{4} d^{2}-6 a \,c^{4} d^{2} x^{4}+9 b \,c^{3} d^{2} x^{3}-4 i x^{2} b \,c^{2} d^{2}+6 x^{2} \arctan \left (c x \right ) b \,c^{2} d^{2}-8 i x \arctan \left (c x \right ) b c \,d^{2}+6 x^{2} d^{2} c^{2} a -8 i a c \,d^{2} x -b c \,d^{2} x -3 b \arctan \left (c x \right ) d^{2}-3 a \,d^{2}}{12 x^{4}}\) | \(185\) |
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Time = 0.25 (sec) , antiderivative size = 155, normalized size of antiderivative = 0.96 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^5} \, dx=\frac {-16 i \, b c^{4} d^{2} x^{4} \log \left (x\right ) + 17 i \, b c^{4} d^{2} x^{4} \log \left (\frac {c x + i}{c}\right ) - i \, b c^{4} d^{2} x^{4} \log \left (\frac {c x - i}{c}\right ) + 18 \, b c^{3} d^{2} x^{3} + 4 \, {\left (3 \, a - 2 i \, b\right )} c^{2} d^{2} x^{2} - 2 \, {\left (8 i \, a + b\right )} c d^{2} x - 6 \, a d^{2} + {\left (6 i \, b c^{2} d^{2} x^{2} + 8 \, b c d^{2} x - 3 i \, b d^{2}\right )} \log \left (-\frac {c x + i}{c x - i}\right )}{24 \, x^{4}} \]
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Time = 8.59 (sec) , antiderivative size = 275, normalized size of antiderivative = 1.71 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^5} \, dx=- \frac {2 i b c^{4} d^{2} \log {\left (1485 b^{2} c^{9} d^{4} x \right )}}{3} - \frac {i b c^{4} d^{2} \log {\left (1485 b^{2} c^{9} d^{4} x - 1485 i b^{2} c^{8} d^{4} \right )}}{24} + \frac {17 i b c^{4} d^{2} \log {\left (1485 b^{2} c^{9} d^{4} x + 1485 i b^{2} c^{8} d^{4} \right )}}{24} + \frac {\left (- 6 i b c^{2} d^{2} x^{2} - 8 b c d^{2} x + 3 i b d^{2}\right ) \log {\left (i c x + 1 \right )}}{24 x^{4}} + \frac {\left (6 i b c^{2} d^{2} x^{2} + 8 b c d^{2} x - 3 i b d^{2}\right ) \log {\left (- i c x + 1 \right )}}{24 x^{4}} - \frac {3 a d^{2} - 9 b c^{3} d^{2} x^{3} + x^{2} \left (- 6 a c^{2} d^{2} + 4 i b c^{2} d^{2}\right ) + x \left (8 i a c d^{2} + b c d^{2}\right )}{12 x^{4}} \]
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Time = 0.30 (sec) , antiderivative size = 152, normalized size of antiderivative = 0.94 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^5} \, dx=\frac {1}{2} \, {\left ({\left (c \arctan \left (c x\right ) + \frac {1}{x}\right )} c + \frac {\arctan \left (c x\right )}{x^{2}}\right )} b c^{2} d^{2} + \frac {1}{3} i \, {\left ({\left (c^{2} \log \left (c^{2} x^{2} + 1\right ) - c^{2} \log \left (x^{2}\right ) - \frac {1}{x^{2}}\right )} c - \frac {2 \, \arctan \left (c x\right )}{x^{3}}\right )} b c d^{2} + \frac {1}{12} \, {\left ({\left (3 \, c^{3} \arctan \left (c x\right ) + \frac {3 \, c^{2} x^{2} - 1}{x^{3}}\right )} c - \frac {3 \, \arctan \left (c x\right )}{x^{4}}\right )} b d^{2} + \frac {a c^{2} d^{2}}{2 \, x^{2}} - \frac {2 i \, a c d^{2}}{3 \, x^{3}} - \frac {a d^{2}}{4 \, x^{4}} \]
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\[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^5} \, dx=\int { \frac {{\left (i \, c d x + d\right )}^{2} {\left (b \arctan \left (c x\right ) + a\right )}}{x^{5}} \,d x } \]
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Time = 0.76 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.88 \[ \int \frac {(d+i c d x)^2 (a+b \arctan (c x))}{x^5} \, dx=\frac {d^2\,\left (9\,b\,c^3\,\mathrm {atan}\left (x\,\sqrt {c^2}\right )\,\sqrt {c^2}+b\,c^4\,\ln \left (c^2\,x^2+1\right )\,4{}\mathrm {i}-b\,c^4\,\ln \left (x\right )\,8{}\mathrm {i}\right )}{12}-\frac {\frac {d^2\,\left (3\,a+3\,b\,\mathrm {atan}\left (c\,x\right )\right )}{12}+\frac {d^2\,x\,\left (a\,c\,8{}\mathrm {i}+b\,c+b\,c\,\mathrm {atan}\left (c\,x\right )\,8{}\mathrm {i}\right )}{12}-\frac {d^2\,x^2\,\left (6\,a\,c^2+6\,b\,c^2\,\mathrm {atan}\left (c\,x\right )-b\,c^2\,4{}\mathrm {i}\right )}{12}-\frac {3\,b\,c^3\,d^2\,x^3}{4}}{x^4} \]
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